Modeling Bluetooth constraints: an example

• 5 slaves (d = 1)
• 2 bridges (d = 2, 3)
• 3 masters

• slave = ( y1 + y2 + y3)

• bridge 1 = (y1y2 + y1y3 + y2y3)

• bridge 2 = (y1y2y3)

x7

x6

x4

x3

y1

x1

x2

x5

y2

P = (y1 + y2 + y3)5(y1y2 + y1y3 + y2y3)1(y1y2y3)1

y3

there are 56 possible choices of bridge nodes, so total number of ways = 56.35.3.1

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